Given: A is below E, B is below A, D is between A and E, and C is above D.
Arrangement (fixed order):
E is above D, D is above A, A is above B
So: E > D > A > B
Now place C:
C must be above D, so C can be:
1) Above E → C becomes the top book
2) Between E and D → E becomes the top book
Therefore, the book(s) that can be on the top: C or E
Given:
B is taller than E but shorter than D → D > B > E
A is shorter than C but taller than D → C > A > D
Combined order (tallest to shortest):
C > A > D > B > E
4th from the tallest: B
Setup (positions from front): Let position of the front be 1 and last be N.
|a − b| = 6.|b − 4| = 9 ⇒ b = 13 (the other choice −5 is invalid).Now, with b = 13, we need |a − 13| = 6 ⇒ a = 7 or a = 19.
But a = N − 21, so:
• If a = 7, then N = 28.
• If a = 19, then N = 40.
Both satisfy all conditions; the minimum possible is:
From Oldest to Youngest:
Yamini > Rakhi > Shweta > Pooja
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and More.