NIMCET 2014 Previous Year Questions (PYQs) – Page 1 of 12
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The nine alphabets L, M, N, O, P, Q, R, S, and T are assigned to nine integers 1 to 9 not necessarily in
the same order 4 is assigned to P. The difference between P and T is 5. The difference between N and T
is 3.
What is the integer assigned to N?
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4
Solution
Five boys A, B, C, D, E and five girls P, Q, R, S, T are standing in two rows facing each other not
necessarily in the order. E is not at any end. C is to the immediate right of B and D is to the immediate
left of A, who is facing P. There are as many girls between P and Q as between R and S. A is second to the left of
B. S and R are not facing either B or D.
Who is facing B?
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4
Solution
Five boys A, B, C, D, E and five girls P, Q, R, S, T are standing in two rows facing each other not
necessarily in the order. E is not at any end. C is to the immediate right of B and D is to the immediate
left of A, who is facing P. There are as many girls between P and Q as between R and S. A is second to the left of
B. S and R are not facing either B or D.
Who is standing to the immediate right of A?
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2
3
4
Solution
Five boys A, B, C, D, E and five girls P, Q, R, S, T are standing in two rows facing each other not
necessarily in the order. E is not at any end. C is to the immediate right of B and D is to the immediate
left of A, who is facing P. There are as many girls between P and Q as between R and S. A is second to the left of
B. S and R are not facing either B or D.
Which of the following is definitely true?
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4
Solution
Five boys A, B, C, D, E and five girls P, Q, R, S, T are standing in two rows facing each other not
necessarily in the order. E is not at any end. C is to the immediate right of B and D is to the immediate
left of A, who is facing P. There are as many girls between P and Q as between R and S. A is second to the left of
B. S and R are not facing either B or D.
Which pair of boys are standing at the ends of the row?
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4
Solution
The sum of ages of a daughter and mother is 63 yr. Four years back, the mother's age was 4 times that
of daughter's age at that time. What is the present age of the mother?
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4
Solution
A watch gains 10 s in 5 min was set correct at 9.00 am. When the watch indicated 20 min past 7.00 pm
in the same evening, the correct time is
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Solution
Watch gains 10s in 5 min
$\text{Gain rate} = \dfrac{10}{5} = 2 \text{ s per minute}$
$\text{Every } 60 \text{ s real time} \Rightarrow \text{watch shows } 62 \text{ s}$
Watch time elapsed:
$9:00 \text{ am to } 7:20 \text{ pm} = 10 \text{ hr } 20 \text{ min} = 620 \text{ min}$
Real time formula:
$\text{Real time} = \text{Watch time} \times \dfrac{60}{62}$
$= 620 \times \dfrac{60}{62}$
$= \dfrac{37200}{62}$
$= 600 \text{ minutes}$
$= 10 \text{ hours}$
Correct Time:
$9:00 \text{ am} + 10 \text{ hours} = \boxed{7:00 \text{ pm}}$
$\text{Gain rate} = \dfrac{10}{5} = 2 \text{ s per minute}$
$\text{Every } 60 \text{ s real time} \Rightarrow \text{watch shows } 62 \text{ s}$
Watch time elapsed:
$9:00 \text{ am to } 7:20 \text{ pm} = 10 \text{ hr } 20 \text{ min} = 620 \text{ min}$
Real time formula:
$\text{Real time} = \text{Watch time} \times \dfrac{60}{62}$
$= 620 \times \dfrac{60}{62}$
$= \dfrac{37200}{62}$
$= 600 \text{ minutes}$
$= 10 \text{ hours}$
Correct Time:
$9:00 \text{ am} + 10 \text{ hours} = \boxed{7:00 \text{ pm}}$
Father is aged three times more than the age of his son Rohit. After 8 yr, he would be two and a half of
Rohit's age. After further 8 yr, how many times would he be of Rohit's age?
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4
Solution
What is the number that comes next in the series?
1, 2, 3, 6, 11, 20, 37, 68, ?
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4
Solution
Six friends A, B, C, D, E, and F are sitting around a hexagonal table. F, who is sitting exactly opposite
A, is to be immediate right of B, D is between A and B and is exactly opposite to C. All are facing
inside.
Who is sitting opposite to B?
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4
Solution
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