NIMCET Percentages Previous Year Questions (PYQs) – Page 1 of 2
Study Stuff for MCA Examinations
Solution
Increased by 15% ⇒ New value = 1.15x
Given: 1.15x = 161
x = 161 ÷ 1.15
x = 140
✅ Final Answer: The original number is 140.
Solution
Solution
Solution
He gave $40%$ of his salary to his mother:
Amount to mother $= 40%$ of $x = 0.40x$.
Remaining salary after giving to mother:
$= x - 0.40x = 0.60x$.
From this remaining $0.60x$:
He used $7%$ for electronic gadgets:
Amount for gadgets $= 7%$ of $0.60x = 0.07 \times 0.60x = 0.042x$.
He kept $23%$ for monthly expenses:
Amount for expenses $= 23%$ of $0.60x = 0.23 \times 0.60x = 0.138x$.
Total used from the remaining on gadgets and expenses:
$0.042x + 0.138x = 0.18x$.
So the amount transferred to his friend's account:
$= 0.60x - 0.18x = 0.42x$.
Now, sum of the amount given to his mother and transferred to his friend is given as $41000$:
Amount to mother $+ $ amount to friend $= 0.40x + 0.42x = 0.82x$.
So,
$0.82x = 41000$
$x = \dfrac{41000}{0.82} = 50000$.
Therefore, Shiva's monthly salary is 50000.
Solution
Given:
- 60% students passed the half-yearly exam.
- Of them, 70% passed the annual exam.
- From the remaining 40% (who failed half-yearly), 80% passed the annual exam.
Assume total students = 100
✅ From 60 students who passed half-yearly:
→ 70% of 60 = 42 passed annual exam.
✅ From 40 students who failed half-yearly:
→ 80% of 40 = 32 passed annual exam.
✅ Total students who passed annual exam = 42 + 32 = 74
Final Answer: 74%
Solution
Let the total number of students = N
We know,
- 78% students were successful → 22% students failed.
- Number of failures = 176.
So,
22% of N = 176
⇒ 22N / 100 = 176
⇒ N = (176 × 100) / 22 = 800
Total students appeared = 800
Now, 34% got first class:
First class students = 34% of 800
= (34 × 800) / 100
= 272
✅ Final Answer: 272 students got first class.
Solution
Let the original fraction be N/D.
According to the problem:
- Numerator is increased by 25% → New numerator = 1.25N
- Denominator is decreased by 20% → New denominator = 0.8D
So, new fraction =
(1.25N) / (0.8D) = 5/4
Simplify:
(1.25 / 0.8) × (N/D) = 5/4
(1.25 ÷ 0.8) = 1.5625 = 25/16
⇒ (25/16) × (N/D) = 5/4
⇒ N/D = (5/4) × (16/25)
= 80 / 100
= 4/5
✅ Final Answer: The original fraction = 4/5
Solution
Hemant's Monthly Salary Calculation
Step 1: Let Hemant's monthly salary be x.
He deposits 10% in PF ⇒ PF = 0.10x
Remaining salary after PF = 0.90x
Step 2: Savings
He saves 30% of the remaining ⇒ Savings = 0.30 × 0.90x = 0.27x
Remaining after savings = 0.90x - 0.27x = 0.63x
Step 3: Expenses on Medicine and Groceries
The ratio is given: Medicine : Groceries = 3 : 4
Total ratio parts = 3 + 4 = 7
Medicine = (3/7) × 0.63x = 0.27x
Step 4: Given that medicine expense = Rs. 2700
0.27x = 2700
⇒ x = 2700 ÷ 0.27 = ₹10,000
✅ Final Answer: ₹10,000
Solution
Percentage Puzzle: Exam Pass Analysis
Step-by-Step Breakdown:
- Assume total students = 100
- Passed in Half-Yearly = 60 students
- 70% of 60 passed in Annual = 42 students
- Failed in Half-Yearly = 40 students
- 80% of 40 passed in Annual = 32 students
- Total passed in Annual = 42 + 32 = 74 students
✅ Final Answer: 74% of the students passed the annual exam.
Solution
Let the number of cat owners be $C$.
Given, $70\%$ of cat owners also own a dog.
So, number of people who own both cat and dog:
$\frac{70}{100}C=\frac{7C}{10}$
Also, $20\%$ of dog owners also own a cat.
Number of dog owners is $1001$.
So, number of people who own both cat and dog:
$\frac{20}{100}\times 1001$
$=\frac{1}{5}\times 1001$
$=\frac{1001}{5}$
Now,
$\frac{7C}{10}=\frac{1001}{5}$
Multiply both sides by $10$:
$7C=2002$
$C=\frac{2002}{7}$
$C=286$
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