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A doctor said to his compounder “I go to see the patients at their residence after every 3:30 hours. I have already gone to the patient 1:20 hours ago and next time I shall go at 1.40 pm”. At what time this information was given to the compounder by the doctor?
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Solution
Gap between two successive visits = 3 hours 30 minutes.
Let present time = T.
Last visit = T – 1 hour 20 minutes
Next visit = 1:40 p.m.
So:
(Next visit) – (Last visit) = 3 hr 30 min
1:40 p.m. – (T – 1:20) = 3:30
⇒ 1:40 p.m. – 3:30 + 1:20 = T
⇒ 1:40 p.m. – 2:10 = 11:30 a.m.
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