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## NIMCET Previous Year Questions (PYQs)

#### NIMCET Differentiation PYQ

NIMCET PYQ
The function $f(x)=\begin{cases}{{(1+2x)}^{1/x}} & {,x\ne0} \\ {{e}^2} & {,x=0}\end{cases}$, is

NIMCET Previous Year PYQNIMCET NIMCET 2022 PYQ

#### Solution

NIMCET PYQ
If $x^my^n$=$(x+y)^{m+n}$, then $\frac{dy}{dx}$ is

NIMCET Previous Year PYQNIMCET NIMCET 2022 PYQ

#### Solution

NIMCET PYQ
If $y={\tan }^{-1}\lgroup{\frac{3x-{x}^3}{1-3{x}^2}}\rgroup\, ,\, \frac{-1}{\sqrt[]{3}}{\lt}x{\lt}\frac{1}{\sqrt[]{3}}$ then $\frac{dy}{dx}$ is

NIMCET Previous Year PYQNIMCET NIMCET 2021 PYQ

#### Solution

Incorrect question

NIMCET PYQ
If $y=\sin ^{-1}(\frac{{x}^2+1}{\sqrt[]{1+3{x}^2+{x}^4}}),\, (x>0),$ then  $\frac{dy}{dx}$=

NIMCET Previous Year PYQNIMCET NIMCET 2021 PYQ

#### Solution

NIMCET PYQ
Differential coefficient of  with respect to  to

NIMCET Previous Year PYQNIMCET NIMCET 2018 PYQ

#### Solution

NIMCET PYQ
If y = cosx, find dx/dy

NIMCET Previous Year PYQNIMCET NIMCET 2017 PYQ

#### Solution

Let y = (cos x2)2
= 2 (cos x2) sin x2 .2x
= -4 (cos x2) sin x

NIMCET PYQ
The derivative of (x3 + ex + 3x + cotx) with respect to x is

NIMCET Previous Year PYQNIMCET NIMCET 2017 PYQ

#### Solution

Let y=x+ e+ 3+ cotx
Now,
= 3x+ e+ 3x log3 - cosec2 x

NIMCET PYQ
Differentiate [- log(log x),  x > 1] with respect to x

NIMCET Previous Year PYQNIMCET NIMCET 2017 PYQ

#### Solution

Let y = - log(log x), x>1
On differentiating both sides,
= - (log (log x))
(log x)

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