A Place for Latest Exam wise Questions, Videos, Previous Year Papers,

Study Stuff for MCA Examinations

Study Stuff for MCA Examinations

The number (2217)_{8} is equivalent to

Go to Discussion

Pair of 4 Bits

1111= F

1000=8

0100=4

(010010001111)8 =(48F)16

The binary multiplication 00*11 will give

Go to Discussion

The binary equivalent of (234.125)_{10}?

Go to Discussion

Determine the octal equivalent of (432267)_{10}?

Go to Discussion

One Exabyte is equal to …

Go to Discussion

The logic XOR operation of (4AC0)_{16} and (B53F)_{16}
results

Go to Discussion

The greatest number which on dividing
1657 and 2037 leaves remainders 6 and 5
respectively is

Go to Discussion

The first number = (1657 - 6) = 1651

Second number = (2037 - 5) = 2032

Taking the HCF of two numbers 1651, 2032 we get 127.

So, if we divide 1657 and 2037 by 127 we will get remainders 6 and 5 respectively.

Suppose the largest n bit number requires ‘d’ digits in decimal representation. Which of the following relations between ‘n’ and ‘d’ is approximately correct

Go to Discussion

So, ${10}^d{\gt}{2}^n$

Take on both side

$\log _{10}({10}^d)\gt{\log _{10}({2}^n)}^{}$

$d{\gt}n\log _{10}(2)$

‘Floating point representation' is used to represent

Go to Discussion

Each of A, B and C is a different digit among 1 to 9. How many different values of the sum of A, B and C are possible, if **ABA X AA=ACCA** ?

Go to Discussion

Choose the correct option for the remainder when X = 1! + 2! + 3! + ...........+ 100! is divided by 24

Go to Discussion

Insert the missing number: 16, 33, 65, 131, 261, ?

Go to Discussion

**Online Test Series, **

Information About Examination,

Syllabus, Notification

and More.

View More

**Online Test Series, **

Information About Examination,

Syllabus, Notification

and More.

View More