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## NIMCET Previous Year Questions (PYQs)

#### NIMCET Number System PYQ

NIMCET PYQ
The number (2217)8 is equivalent to

NIMCET Previous Year PYQNIMCET NIMCET 2021 PYQ

#### Solution

(2217)8 =(010010001111)8
Pair of 4 Bits
1111= F
1000=8
0100=4
(010010001111)=(48F)16

NIMCET PYQ
The binary multiplication 00*11 will give

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#### Solution

0*3=0

NIMCET PYQ
The binary equivalent of (234.125)10?

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#### Solution

NIMCET PYQ
Determine the octal equivalent of (432267)10?

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#### Solution

NIMCET PYQ
One Exabyte is equal to …

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#### Solution

NIMCET PYQ
The logic XOR operation of (4AC0)16 and (B53F)16 results

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#### Solution

NIMCET PYQ
The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively is

NIMCET Previous Year PYQNIMCET NIMCET 2022 PYQ

#### Solution

The first number = (1657 - 6) = 1651

Second number = (2037 - 5) = 2032

Taking the HCF of two numbers 1651, 2032 we get 127.

So, if we divide 1657 and 2037 by 127 we will get remainders 6 and 5 respectively.

NIMCET PYQ
Suppose the largest n bit number requires ‘d’ digits in decimal representation. Which of the following relations between ‘n’ and ‘d’ is approximately correct

NIMCET Previous Year PYQNIMCET NIMCET 2022 PYQ

#### Solution

n bits binary number required d -decimal digits.

So, ${10}^d{\gt}{2}^n$

Take on both side

$\log _{10}({10}^d)\gt{\log _{10}({2}^n)}^{}$

$d{\gt}n\log _{10}(2)$

NIMCET PYQ
‘Floating point representation' is used to represent

NIMCET Previous Year PYQNIMCET NIMCET 2022 PYQ

#### Solution

NIMCET PYQ
Each of A, B and C is a different digit among 1 to 9. How many different values of the sum of A, B and C are possible, if  ABA X AA=ACCA ?

NIMCET Previous Year PYQNIMCET NIMCET 2019 PYQ

#### Solution

NIMCET PYQ
Choose the correct option for the remainder when X = 1! + 2! + 3! + ...........+ 100! is divided by 24

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#### Solution

NIMCET PYQ
Insert the missing number: 16, 33, 65, 131, 261, ?

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