AMU MCA Properties Of Triangle Previous Year Questions (PYQs)
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Showing 1 question
A polygon has 9 diagonals. Then the number of sides of the polygon is:
1
2
3
4
Solution
Number of diagonals of a polygon $= \frac{n(n-3)}{2}$
$\frac{n(n-3)}{2} = 9$
$n(n-3) = 18$
$n^2 - 3n - 18 = 0$
$(n-6)(n+3) = 0$
$n = 6$
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