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NIMCET 2015

How many 3-digit numbers divisible by 5, can be formed using the digits 2 3 5 6 7 and 9, without repetition of digits?

Solution

A number divisible by 5 must end in 5.

Fix the units digit as 5.

Remaining digits for hundreds and tens places: 2, 3, 6, 7, 9 (5 digits).

Number of ways to choose hundreds and tens digits = 5 × 4 = 20.

Answer: 20

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