Aspire Faculty ID #10281 · Topic: NIMCET 2015 · Just now
NIMCET 2015

The remainder when 231 is divided by 5 is

Solution

Remainder of 231 Divided by 5

To find the remainder of 231 divided by 5, we look at the cycle of powers of 2 mod 5: 2, 4, 3, 1 (repeats every 4 terms).

31 mod 4 = 3, so 231 corresponds to the 3rd term, which is 3.

Answer: 3

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