Aspire Faculty ID #10465 · Topic: NIMCET 2014 · Just now
NIMCET 2014

If the foci of the ellipse $b^{2}x^{2}+16y^{2}=16b^{2}$ and the hyperbola $81x^{2}-144y^{2}=\frac{81 \times 144}{25}$ coincide, then the value of $b$, is

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