Aspire Faculty ID #11203 · Topic: NIMCET 2022 · Just now
NIMCET 2022

If a processor clock is rated as 2500 million cycles per second, then its clock period is:

Solution

we know that Frequency is defined as the number of cycles in one second

Number of cycle in 1 sec = 2500 million

=> Frequency = 2500 Mhz

we know that time period is the inverse of frequency and is defined as the time taken by one cycle.

$T = \frac{1}{F}$

$T = \frac{1}{2500 \times 10^{-6}}$

$T=4 \times 10^{-10} $ sec


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