Aspire Faculty ID #11661 · Topic: NIMCET 2024 · Just now
NIMCET 2024

How much work does it take to slide a crate for a distance of 25m along a loading dock by pulling on it with a 180 N force where the dock is at an angle of $45°$ from the horizontal?

Solution

Work Done Problem:

A crate is pulled 25 m along a dock with a force of 180 N at an angle of 45°.

✅ Formula Used:

\[ \text{Work} = F \cdot d \cdot \cos(\theta) \]

✅ Substituting Values:

\[ W = 180 \times 25 \times \cos(45^\circ) = 180 \times 25 \times 0.70710678118 = 3181.98052\, \text{J} \]

✅ Final Answer (to 5 decimal places):

\[ \boxed{3.181\times 10^3 \, \text{Joules}} \]

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