Aspire Faculty ID #12010 · Topic: NIMCET 2025 · Just now
NIMCET 2025

A remote island has a unique social structure. Individuals are either 'Truth-tellers' (who always speak the truth) or 'Tricksters' (who always lie). You encounter three inhabitants: X, Y, and Z.

X says: "Y is a Trickster."
Y says: "Exactly one of us is a Truth-teller."
What can you definitively conclude about Z?

Solution

Let me quickly re-check the logic:

  1. Let T = Truth-teller, L = Trickster (liar).

X says: “Y is a Trickster.”
Y says: “Exactly one of us (X, Y, Z) is a Truth-teller.”


Case 1: Assume X is T.
Then Y must be L.
Y’s statement must be false: “Exactly one of us is a Truth-teller” is false.

  • Truth-tellers so far: X (1).
    If Z were L, then exactly one (X) would be T → Y’s statement would be true, contradiction.
    So Z must be T.
    Configuration: (X T, Y L, Z T) works.

Case 2: Assume X is L.
Then “Y is a Trickster” is false → Y is T.
Now Y’s statement must be true: exactly one of X, Y, Z is T.

  • We already have Y as T, so X and Z must both be L.
    Configuration: (X L, Y T, Z L) works.


Both configurations are consistent:

  • In one, Z is T.

  • In the other, Z is L.

So Z can be either a Truth-teller or a Trickster

Previous 10 Questions — NIMCET 2025

Nearest first

Next 10 Questions — NIMCET 2025

Ascending by ID
Ask Your Question or Put Your Review.

loading...