Aspire Faculty ID #12025 · Topic: NIMCET 2025 · Just now
NIMCET 2025

A person walks 8 km north, turns right, walks 4 km, turns right again and walks 6 km. Finally, he turns left and walks 3 km. How far is he from the starting point?

Solution

A person walks $8$ km north. 
 Position: $(0,\,8)$ 
 He turns right (east) and walks $4$ km. 
 Position: $(4,\,8)$ 
 He turns right again (south) and walks $6$ km. 
 Position: $(4,\,2)$ 
 He turns left (east) and walks $3$ km. 
 Final position: $(7,\,2)$ 
 Distance from starting point: 
 $ d = \sqrt{(7-0)^2 + (2-0)^2} $ 
 $ d = \sqrt{49 + 4} $ 
 $ d = \sqrt{53} $ 
 $d=7.28$

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