Aspire Faculty ID #14007 · Topic: JAMIA MILLIA ISLAMIA MCA 2019 · Just now
JAMIA MILLIA ISLAMIA MCA 2019

If $(41)_8 = (121)_b$, then $b$ is:

Solution

$(41)_8 = 4\times8 + 1 = 33_{10}$ Now, $(121)_b = 1\times b^2 + 2\times b + 1 = b^2 + 2b + 1$ Equating, $b^2 + 2b + 1 = 33$ $\Rightarrow b^2 + 2b - 32 = 0$ $\Rightarrow (b - 4)(b + 8) = 0 \Rightarrow b = 4$
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