Aspire Faculty ID #16178 · Topic: NIMCET 2011 · Just now
NIMCET 2011

$A$ polygon has $44$ diagonals, the number of its sides is

Solution

Number of diagonals $=\dfrac{n(n-3)}{2}=44$ $\Rightarrow n(n-3)=88$ $\Rightarrow n^2-3n-88=0$ $\Rightarrow (n-11)(n+8)=0$ So $n=11$

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