Aspire Faculty ID #16222 · Topic: NIMCET 2011 · Just now
NIMCET 2011

Let: $ X = 2^{100},\quad Y = 3^{100},\quad Z = 4^{100} $ Which statement is true?

Solution

$ Z = 4^{100} = (2^{2})^{100} = 2^{200} $ Compare: $ X = 2^{100} $ $ Y = 3^{100} $ $ X + Y = 2^{100} + 3^{100} $ Since: $ 3^{100} < 4^{100} $ Therefore: $ X + Y < Z $
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