Aspire Faculty ID #16412 · Topic: NIMCET 2009 · Just now
NIMCET 2009

A square with side $a$ is revolved about its centre through $45^\circ$. What is the area common to both the squares?

Solution

The overlapping area of a square rotated by $45^\circ$ is: Common area $= 2(\sqrt{2}-1)a^2$

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