Aspire Faculty ID #16413 · Topic: NIMCET 2009 · Just now
NIMCET 2009

A and B throw a die in succession to win a bet with A starting first. Whoever throws ‘1’ first wins Rs. 110. What are the respective expectations of A and B?

Solution

Let $P_A$ = probability A wins. 
 $P_A = \dfrac{1}{6} + \dfrac{5}{6}\cdot\dfrac{5}{6} P_A$ 
 Solving: $P_A = \dfrac{6}{11}$ 
$P_B = \dfrac{5}{11}$ 
 Expected money: 
$E_A = 110 \cdot \dfrac{6}{11} = 60$ 
$E_B = 110 \cdot \dfrac{5}{11} = 50$

Previous 10 Questions — NIMCET 2009

Nearest first

Next 10 Questions — NIMCET 2009

Ascending by ID
Ask Your Question or Put Your Review.

loading...