Aspire Faculty ID #16545 · Topic: NIMCET 2008 · Just now
NIMCET 2008

If $f(x)+f(1-x)=2$, then the value of $f\left(\dfrac{1}{2001}\right)+f\left(\dfrac{2}{2001}\right)+\cdots+f\left(\dfrac{2000}{2001}\right)$ is

Solution

Terms pair as $f\left(\frac{k}{2001}\right)+f\left(1-\frac{k}{2001}\right)=2$ There are $1000$ such pairs. Sum $=1000\times2=2000$ Answer: $\boxed{2000}$

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