Aspire Faculty ID #17100 · Topic: AMU MCA 2021 · Just now
AMU MCA 2021

Let $E(X)=\mu$, $Var(X)=9$. Smallest $m$ such that $P(|X-\mu|

Solution

Using Chebyshev inequality:

$P(|X-\mu|\ge m)\le \frac{Var(X)}{m^2}$

$1-\frac{9}{m^2}\ge 0.99$

$\frac{9}{m^2}\le 0.01$

$m^2\ge 900$

$m=30$

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