Aspire Faculty ID #18332 · Topic: AMU MCA 2017 · Just now
AMU MCA 2017

The total revenue in rupees received from the sale of $x$ units of a product is given by $R(x)=5x^2+20x+7$. The marginal revenue, when $x=8$ is

Solution

$MR=\frac{dR}{dx}=\frac{d}{dx}(5x^2+20x+7)=10x+20$ At $x=8$ $MR=10(8)+20=80+20=100$

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