Aspire Faculty ID #18679 · Topic: NIMCET 2026 · Just now
NIMCET 2026

The arithmetic mean of two numbers a and b is 5, and the harmonic mean is 3.2. Find the numbers a and b.

Solution

AM $=5$

$\frac{a+b}{2}=5$

$a+b=10$

HM $=3.2$

$\frac{2ab}{a+b}=3.2$

$\frac{2ab}{10}=3.2$

$ab=16$

Therefore, $a$ and $b$ are roots of

$x^2-10x+16=0$

$(x-8)(x-2)=0$

$\boxed{a=8,\quad b=2}$

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