The set $ (A \Delta B) \cap C $ is not equal to:

We know that
$A \Delta B = (A \cap B^c) \cup (A^c \cap B)$

Now,
$(A \Delta B) \cap C = [(A \cap B^c) \cup (A^c \cap B)] \cap C$

Using distributive law,
$(A \Delta B) \cap C = (A \cap B^c \cap C) \cup (A^c \cap B \cap C)$

Option $1$, option $2$ and option $4$ represent the same set.

But option $3$ is
$(A \cap B)^c \cap C$

This means all elements of $C$ except the elements common in $A$ and $B$.
It also includes elements which are neither in $A$ nor in $B$, but present in $C$.

So, it is not equal to $ (A \Delta B) \cap C $.