Aspire Faculty ID #19185 · Topic: NIMCET 2026 · Just now
NIMCET 2026

Five years ago, $A$ was three times as old as $B$. Now, $A$ is twice as old as $B$. What is $A$'s current age in years?

Solution

Let the present age of $B$ be $x$ years.

Then present age of $A$ is:

$2x$

Five years ago,

Age of $A=2x-5$

Age of $B=x-5$

According to the question:

$2x-5=3(x-5)$

$2x-5=3x-15$

$3x-2x=15-5$

$x=10$

So, present age of $A$ is:

$2x=2(10)=20$

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