Aspire Faculty ID #3779 · Topic: NIMCET 2018 · Just now
NIMCET 2018

Let $\alpha$ and $\beta$ be the roots of the equation $x^2 - px + r = 0$ and $\dfrac{\alpha}{2}, 2\beta$ are the roots of the equation $x^2 - qx + r = 0$, then the value of $r$,

Solution


Previous 10 Questions — NIMCET 2018

Nearest first

Next 10 Questions — NIMCET 2018

Ascending by ID
Ask Your Question or Put Your Review.

loading...
Aman Agrahari
Aman Agrahari , Batch Three
Commented Jun 26, 2020
post_txt

Your reply to this comment:


loading...