Aspire Faculty ID #4314 · Topic: NIMCET 2017 · Just now
NIMCET 2017

Differentiate [- log(log x),  x > 1] with respect to x

Solution

Let $y=-\log(\log x)$

$\dfrac{dy}{dx}=-\dfrac{d}{dx}[\log(\log x)]$

$\dfrac{d}{dx}[\log(\log x)]=\dfrac{1}{\log x}\cdot\dfrac{1}{x}$

Therefore, $\dfrac{dy}{dx}=-\dfrac{1}{x\log x}$

Answer: $\boxed{-\dfrac{1}{x\log x}},\; x>1$ ✅

Previous 10 Questions — NIMCET 2017

Nearest first

Next 10 Questions — NIMCET 2017

Ascending by ID
Ask Your Question or Put Your Review.

loading...