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Question Id : 11502 | Context :NIMCET 2023

Question

A computer producing factory has only two plants T1 and T2. Plant T1 produces 20% and plant T2 produces 80% of total computers produced. 7% of computers produced in the factory turn out to be defective. It is known that P (computer turns out to be defective given that it is produced in plant T1) = 10P (computer turns out to be defective given that it is produced in plant T2). where P(E) denotes the probability of an event E. A computer produced in the factory is randomly selected and it does not turn out to be defective. Then the probability that it is produced in plant T2 is
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