Median & Frequency Table

Given: Median = 42.6, Total Frequency = 685

Using Median Formula:

\( \text{Median} = L + \left( \frac{N/2 - F}{f} \right) \cdot h \)

• Median Class: 40–50
• Lower boundary \( L = 40 \)
• Frequency \( f = 180 \)
• Class width \( h = 10 \)
• Cumulative freq before median class \( F = 214 + f_1 \)

Substituting values:

\( 42.6 = 40 + \left( \frac{128.5 - f_1}{180} \right) \cdot 10 \Rightarrow f_1 = \boxed{82} \)

Using total frequency:

\( 662 + f_2 = 685 \Rightarrow f_2 = \boxed{23} \)

✅ Final Answer: \( f_1 = 82,\quad f_2 = 23 \)