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Given: →a,→b are unit vectors and
2→a+→b=3
Take magnitude on both sides:
|2→a+→b|=3⇒|2→a+→b|2=9
Use identity:
|2→a+→b|2=4|→a|2+|→b|2+4(→a⋅→b)=4+1+4(→a⋅→b)=5+4(→a⋅→b)
Set equal to 9:
5+4(→a⋅→b)=9⇒→a⋅→b=1⇒cosθ=1⇒θ=0∘
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