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sinx=sinyandcosx=cosy
sinx=siny⇒x=y+2nπorx=π−y+2nπ
cosx=cosy⇒x=y+2mπorx=−y+2mπ
For both sinx=siny and cosx=cosy to be true, the only consistent solution is:
x=y+2nπ⇒x−y=2nπ
x−y=2nπfor n∈Z
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