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Question Id : 11654 | Context :NIMCET 2024

Question

A coin is thrown 8 number of times. What is the probability of getting a head in an odd number of throw?
🎥 Video solution / Text Solution of this question is given below:

Total outcomes = 28=256

Favorable outcomes (odd heads):

  • \binom{8}{1} = 8
  • \binom{8}{3} = 56
  • \binom{8}{5} = 56
  • \binom{8}{7} = 8

Total favorable = 8 + 56 + 56 + 8 = 128

So, Probability = \frac{128}{256} = \boxed{\frac{1}{2}}

? Final Answer: \boxed{\frac{1}{2}}



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