Bala had three sons. He had some chocolates which he distributed among them. To his eldest son, he gave 3 chocolates more than half the number of chocolates with him. To his second eldest son he gave 4 chocolates more than one third of the remaining number of chocolates with him. To his youngest son he gave 4 chocolates more than one fourth of the remaining number of chocolates with him. He was left with 11 chocolates. How many chocolates did he initially have?
🎥 Video solution / Text Solution of this question is given below:
Let total chocolates = x.
After giving to first son:
He gives (x/2 + 3), remaining = x – (x/2 + 3) = x/2 – 3
To second son he gives (1/3 of remaining + 4):
Remaining after second son = (x/2 – 3) – [(x/6 – 1) + 4] = x/3 – 6