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Question Id : 3771 | Context :NIMCET 2018

Question

9 balls are to be placed in 9 boxes and 5 of the balls cannot fit into 3 small boxes. The number of ways of arranging one ball in each of the boxes is

🎥 Video solution / Text Solution of this question is given below:

First off all select 5 boxes out 6 boxes in which 5 big ball can fit then arrange these ball in these 5 boxes and then put remaining 4 ball in any remaining box. 
So Ans is [(6C5)5!](4!) = 6!4! = 17280


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