In a beauty contest, half the number of experts voted Mr. A and two thirds voted for Mr. B 10 voted for both and 6 did not for either. How may experts were there in all.
🎥 Video solution / Text Solution of this question is given below:
Let the total number of experts be N.
E is the set of experts who voted for miss A.
F is the set of experts who voted for miss B.
Since 6 did not vote for either, n(E∪F)=N−6.
n(E)=N2,n(F)=23N and n(E∩F)=10
.
So, N−6=N2+23N−10
Solving the above equation gives N6=4⇒N=24