Aspire's Library

A Place for Latest Exam wise Questions, Videos, Previous Year Papers,
Study Stuff for MCA Examinations - NIMCET


Best NIMCET Coaching
Aspire Study
Online Classes, Classroom Classes
and More.

Previous Year Question (PYQs)



Using only 2, 5, 10, 25 and 50 paise coins, the smallest number of coins required to pay exactly 79 paise, 66 paise and Re 1.01 to three different persons is





Solution

Coins For 79 Paise : 
25 paise × 3 coins + 2 paise × 2 coins Total number of coins for 79 paise = 5 
Coins For 66 Paise : 
50 paise × 1 coin + 10 paise × 1 coin + 2 paise × 3 coin 
Total number of coins for 66 paise = 5 coins 
For 1.01 Paise : 
50 paise × 1 coin + 25 paise × 1 coin + 10 paise × 2 coin + 2 paise × 3 coin 
Total number of coins for Rs. 1.01 paise = 7 coins 
So, total coins used = (5 + 5 + 7) coins 
= 17 coins 
Ans.(A) (because given that smallest no. of coin)


Aspire Study Online Test Series,
Information About Examination,
Syllabus, Notification
and More.

Click Here to
View More


Aspire Study Online Test Series,
Information About Examination,
Syllabus, Notification
and More.

Click Here to
View More

Ask Your Question or Put Your Review.

loading...