Aspire's Library
A Place for Latest Exam wise Questions, Videos, Previous Year Papers,
Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Best NIMCET Coaching Aspire Study
Online Classes, Classroom Classes
and More.
Aspire Study Library
Question
Using only 2, 5, 10, 25 and 50 paise coins, the smallest number of coins required to pay exactly 79 paise, 66 paise and Re 1.01 to three different persons is
🎥 Video solution / Text Solution of this question is given below:
Coins For 79 Paise :
25 paise × 3 coins + 2 paise × 2 coins
Total number of coins for 79 paise = 5
Coins
For 66 Paise :
50 paise × 1 coin + 10 paise × 1 coin + 2 paise × 3 coin
Total number of coins for 66 paise = 5 coins
For 1.01 Paise :
50 paise × 1 coin + 25 paise × 1 coin + 10 paise × 2 coin
+ 2 paise × 3 coin
Total number of coins for Rs. 1.01 paise = 7 coins
So, total coins used = (5 + 5 + 7) coins
= 17 coins
Ans.(A) (because given that smallest no. of coin)
Aspire Study Online Test Series, Information About Examination,
Syllabus, Notification
and More.
View More
Aspire Study Online Test Series, Information About Examination,
Syllabus, Notification
and More.
View More
Ask Your Question or Put Your Review.
