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Consider the equation (40)x = (132)y is some bases x and y. Then a possible set of value of x and y are





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$\begin{array}{ll}{{{(40})}_x={{(132)}}_y} \\ {\Rightarrow4\times{x}^1}+0\times{x}^0=1\times{y}^2+3\times{y}^1+2\times{y}^0 \\ {\Rightarrow4x+0={y}^2+3y^{}+2} \\ {4x={y}^2+3y^{}+2}\end{array}$


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Manmohan dwivedi-pic
Manmohan dwivedi , Nimcet
Commented May 21 , 2022
approx every question has mistakes, pata nahi ya fook k typing kri h kisi ne

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Vinay-pic
Vinay , Student
Commented Feb 28 , 2021
Ans d , is correct 4x = y**2+3y+2 ,,,. This equation will only satisfying with option d .

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