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Four friends A, B, C and D need to cross a bridge in the night. A maximum of 2 people can cross at a time. They have only one lamp. A takes one minute to cross the bridge. B takes 2 minutes, C takes 8 minutes and D takes 11 minutes to cross the bridge respectively. A pair must walk together at the speed of the person who walks slowly. What is the minimum time required to cross the bridge by all the four people?





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Sourav Barnwal-pic
Sourav Barnwal ,
Commented Jul 31 , 2023
A and B cross the bridge together (2 minutes). A goes back with the lamp (1 minute). C and D cross the bridge together (11 minutes). B returns with the lamp (2 minutes). A and B cross the bridge together again (2 minutes). The total minimum time required for all four people to cross the bridge is 2 + 1 + 11 + 2 + 2 = 18 minutes.

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Abdul mannan-pic
Abdul mannan , Mca aisprint
Commented Dec 12 , 2022
A pair must walk together at the speed of the person who walks slowly. As A takes the shortest time, so each friend will walk with A. Time taken: A crossing the bridge with B and then retuning = 1 + 2 minutes = 3 minutes A crossing the bridge with C and then retuning = 1 + 8 minutes = 9 minutes A crossing the bridge with D = 11 minutes A won’t return as none of the friend is left. So, the minimum time required to cross the bridge by all the four people = (3 + 9 + 11) minute = 23 minutes
Sample Account-pic
Sample Account , Other
Commented Jan 27 , 2024
Your answer should be optimised.

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Aditya Pandey-pic
Aditya Pandey , Part Time SDE Intern
Commented Mar 26 , 2022
Here's my solution : A and B = +2 mins A Runs back = +1 min A gives lamp to C and D = +11 mins B runs back = +2 mins A and B = +2min 2+1+11+2+2 = 18 mins

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Ajay Kumar Singh-pic
Ajay Kumar Singh , Verified by FTT
Commented Jul 16 , 2021
ans will be 23min

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Lovepreet Singh-pic
Lovepreet Singh , studying BCA
Commented May 31 , 2021
Correct answer should be 23 min

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Lovepreet Singh-pic
Lovepreet Singh , studying BCA
Commented May 31 , 2021
hiabcdefgh

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