[Video Solution] Number of solutions for \tan^-1√x(x+1) + \sin^-1√x^2 + x + 1 = \dfracπ2 is: | ASPIRE STUDY

Name: [Video Solution] Number of solutions for \tan^-1√x(x+1) + \sin^-1√x^2 + x + 1 = \dfracπ2 is: | ASPIRE STUDY
Uploaded: 2026-10-20T10:09:47+00:00
Description: Number of solutions for \tan^-1√x(x+1) + \sin^-1√x^2 + x + 1 = \dfracπ2 is: | Watch the step-by-step video solution for this NIMCET PYQ.

Number of solutions for \tan^-1√x(x+1) + \sin^-1√x^2 + x + 1 = \dfracπ2 is: | Watch the step-by-step video solution for this NIMCET PYQ.

Published: 2026-10-20T10:09:47+00:00 Thumbnail: Open Page: https://myaspirestudy.com/library/video/16444/number-of-solutions-for-tan-1-x-x-1-sin-1-x-2-x-1-dfrac-2-is

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