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If a_1,a_2,\ldots,a_n are in A.P. and a_1=0 then the value of \left(\dfraca_3a_2+\dfraca_4a_3+*s+\dfraca_na_n-1\right)-a_2\left(\dfrac1a_2+\dfrac1a_3+*s+\dfrac1a_n-2\right) is equal to | Watch the step-by-step video solution for this NIMCET PYQ.