Aspire Faculty ID #11974 · Topic: NIMCET 2025 · Just now
NIMCET 2025

The maximum value of $\sin x+\sin(x+1)$ is $k \cos \frac{1}{2}$. Then the value of k is 

Solution

We use the identity
 $\sin A + \sin B = 2 \sin \dfrac{A+B}{2} \cos \dfrac{A-B}{2}$. 
So, $\sin x + \sin(x+1) = 2 \sin\left(x+\dfrac12\right)\cos\dfrac12$. 
Maximum value of $\sin(x+\tfrac12)$ is $1$. 
Therefore maximum of the expression is: $2 \cos\dfrac12$. 
Given maximum $= k \cos\dfrac12$, so $k = 2$. 

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