Aspire Faculty ID #16172 · Topic: NIMCET 2011 · Just now
NIMCET 2011

Mean of first $n$ natural numbers $=\dfrac{n+7}{3}$. Find $n$:

Solution

Mean $=\dfrac{n+1}{2}=\dfrac{n+7}{3}$ Cross-multiply: $3(n+1)=2(n+7)$ $3n+3=2n+14$ $n=11$

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