Aspire Faculty ID #16302 · Topic: NIMCET 2010 · Just now
NIMCET 2010

If $a, b, c$ are in A.P., $p, q, r$ are in H.P. and $ap, bq, cr$ in G.P.$,$ then $\frac{p}{r} + \frac{r}{p}$ is equal to

Solution

$a, b, c$ in A.P. 
⇒ $b = \frac{a+c}{2}$ 

$p, q, r$ in H.P. 
⇒ $\frac{1}{p}, \frac{1}{q}, \frac{1}{r}$ in A.P. 

 Given $ap, bq, cr$ in G.P.

 $\frac{bq}{ap} = \frac{cr}{bq}$ 

 Substitute $b = \frac{a+c}{2}$ and simplify: $\frac{p}{r} + \frac{r}{p} = \frac{a}{c} + \frac{c}{a}$

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