Aspire Faculty ID #16305 · Topic: NIMCET 2010 · Just now
NIMCET 2010

The point $(4,1)$ undergoes the following transformations successively: (i) Reflection about the line $y=x$ (ii) Translation through a distance $2$ units along the positive $x$-axis (iii) Rotation by an angle $\frac{\pi}{4}$ anticlockwise about the origin The final position of the point is:

Solution

Solution: Step 1: Reflect (4,1) about y=x → (1,4) Step 2: Translate 2 units in +x direction → (1+2, 4) = (3,4) Step 3: Rotate (3,4) by π/4 anticlockwise: New x = (3 - 4)/√2 = -1/√2 New y = (3 + 4)/√2 = 7/√2 Final point = $\left(\frac{-1}{\sqrt{2}}, \frac{7}{\sqrt{2}}\right)$

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