Aspire Faculty ID #16316 · Topic: NIMCET 2010 · Just now
NIMCET 2010

$I_1 = \int_{0}^{1} 2x^2 dx,\ I_2 = \int_{0}^{1} 2x^3 dx,\ I_3 = \int_{1}^{2} x^2 dx,\ I_4 = \int_{1}^{2} 2x^3 dx$

Solution

$I_1 = \left[\frac{2x^3}{3}\right]_{0}^{1} = \frac{2}{3}$ $I_2 = \left[\frac{2x^4}{4}\right]_{0}^{1} = \frac{1}{2}$ Thus $I_1 > I_2$ $I_3 = \left[\frac{x^3}{3}\right]_{1}^{2} = \frac{8}{3} - \frac{1}{3} = \frac{7}{3}$ $I_4 = \left[\frac{2x^4}{4}\right]_{1}^{2} = 4 - \frac{1}{2} = \frac{7}{2}$ Thus $I_4 > I_3$

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