Aspire Faculty ID #16325 · Topic: NIMCET 2010 · Just now
NIMCET 2010

In $\triangle ABC$, $R$ is circumradius and $8R^2=a^2+b^2+c^2$. Then $\triangle ABC$ is:

Solution

In any triangle: $a^2+b^2+c^2 = 8R^2$ ⇔ right-angled triangle identity.

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