Aspire Faculty ID #16435 · Topic: NIMCET 2009 · Just now
NIMCET 2009

If $A = \begin{bmatrix} 1 & 2 \\ 3 & 4 \end{bmatrix}$, then $I + A + A^2 + A^3 + \cdots \infty$ equals:

Solution

Since $I + A + A^2 + \cdots = (I - A)^{-1}$, 
 $I - A = \begin{bmatrix} 0 & -2 \\ -3 & -3 \end{bmatrix}$ 
 $(I - A)^{-1} = \begin{bmatrix} \tfrac{1}{2} & -\tfrac{1}{3} \\ -\tfrac{1}{2} & 0 \end{bmatrix}$.

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