Aspire Faculty ID #16437 · Topic: NIMCET 2009 · Just now
NIMCET 2009

$ABC$ is isosceles with $AB = AC$. $BC$ is parallel to x-axis. $m_1, m_2$ are slopes of the medians from $B$ and $C$. Then:

Solution

Let coordinates: $B(-a, 0)$ $C(a, 0)$ $A(0, h)$ 
 Median from $B$ goes to midpoint of $AC$: $(0, h/2)$ 
Slope: $m_1 = \dfrac{h/2 - 0}{0 - (-a)} = \dfrac{h}{2a}$ 

 Median from $C$ goes to midpoint of $AB$: $(0, h/2)$ 
Slope: $m_2 = \dfrac{h/2 - 0}{0 - a} = -\dfrac{h}{2a}$ 

 Thus: $m_1 + m_2 = 0$

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