Aspire Faculty ID #16211 · Topic: NIMCET 2011 · Just now
NIMCET 2011

Solve: $ 2\sin^{2}\theta - 3\sin\theta - 2 = 0$

Solution

Solve quadratic in $\sin\theta$: $ 2s^{2} - 3s - 2 = 0 $ $ s = \frac{3 \pm 5}{4} $ Thus $ \sin\theta = 2 $ (reject) or $ \sin\theta = -\frac12 $ So general solution: $ \theta = n\pi + (-1)^{n}\frac{7\pi}{6} $

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